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Question Number 195087 by bett last updated on 23/Jul/23

Answered by JDamian last updated on 23/Jul/23

Answered by Rasheed.Sindhi last updated on 23/Jul/23

log_3 4x+3log_(27) x=−6 log_3 4x+3(((log_3 x)/(log_3 27 )))=−6 log_3 4x+3(((log_3 x)/(3 )))=−6 log_3 4x+log_3 x=−6 log_3 (4x^2 )=−6 3^(−6) =4x^2 x^2 =(3^(−6) /4)=(1/(4∙3^6 )) x=(1/(2.3^3 ))=(1/(54))

log34x+3log27x=−6log34x+3(log3xlog327)=−6log34x+3(log3x3)=−6log34x+log3x=−6log3(4x2)=−63−6=4x2x2=3−64=14⋅36x=12.33=154

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