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Question Number 195093 by Braulio last updated on 24/Jul/23

Answered by cortano12 last updated on 24/Jul/23

Answered by MM42 last updated on 24/Jul/23

$$hop\to {lim}_{x\to \pi }\frac{\frac{1}{2}cos\frac{x}{2}-sinx}{2sinxcosx-sinx}$$$$={lim}_{x\to \pi }\frac{cos\frac{x}{2}(\frac{1}{2}-2sin\frac{x}{2})}{cos\frac{x}{2}(4sin\frac{x}{2}cosx-2sin\frac{x}{2})}$$$$=\frac{1}{4}✓$$

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