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Question Number 195097 by Rupesh123 last updated on 24/Jul/23

Answered by Rasheed.Sindhi last updated on 24/Jul/23

$${49}^{\sin x}=\sqrt[\cos x]{7}$$$$7^{2\sin x}=7^{\frac{1}{\cos x}}$$$$2\sin x=\frac{1}{\cos x}$$$$2\sin x\cos x=1$$$$\sin \left(2x\right)=1$$$$2x=\frac{\pi }{2}+2n\pi$$$$x=\frac{\pi }{4}+n\pi$$

Commented by Rupesh123 last updated on 24/Jul/23

Nice!

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