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Question Number 195114 by mustafazaheen last updated on 24/Jul/23

$$$$$$$$$$\underset{\mathrm{k}=3}{\sum ^{55}}\mathrm{k}=?$$$$1)552)9\mathrm{k}3)53\mathrm{k}4)45$$$$$$$$$$

Answered by cortano12 last updated on 25/Jul/23

$$\underset{k=3}{\sum ^{55}}k=\underset{k=1}{\sum ^{55}}k-\underset{k=1}{\sum ^2}k$$$$=\frac{55\times 54-2\times 1}{2}=55\times 27-1$$

Answered by JDamian last updated on 25/Jul/23

$$3+4+\cdot \cdot \cdot +54+55=\frac{3+55}{2}\times 53$$

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