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Question Number 195192 by mustafazaheen last updated on 26/Jul/23

$$$$$$\underset{x\to \mathrm{\infty }}{\lim }{(\mathrm{sinx}+\frac{\pi }{2})}^{\mathrm{x}}=?$$

Answered by MM42 last updated on 26/Jul/23

$$sinx+\frac{\pi }{2}>1$$$$\Rightarrow {lim}_{x\to +\mathrm{\infty }}=+\mathrm{\infty }\mathrm{\&}{lim}_{x\to -\mathrm{\infty }}=0$$

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