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Question Number 195194 by Abdullahrussell last updated on 26/Jul/23
Answered by Frix last updated on 26/Jul/23
abcd231510241262612421015332101533663663315102426124444412626241263366633612421023151015321242612624153210151023
Answered by deleteduser1 last updated on 27/Jul/23
WLOG,letabethemaximumac=a+b+c+d⩽4a⇒c⩽4;c=1⇒b+d=−1(absurd)c=2⇒b+d=a−2and2a=bdbanddsatisfyx2−(a−2)x+2a=0b,d=(a−2)+−a2−12a+42∈Z+⇒a2−12a+4=p2(a−6)2−32=p2⇒(a−6−p)(a−6+p)=32=1×32=2×16=3×8...(uptopermutation,negativefactors)Z+solutions:(a,p)=(12,2),(15,7)⇒b,d=10+−22=6or4OR13+−72=10or3c=3⇒b+d=2a−3and3a=bd⇒b,d=(2a−3)+−4a2−24a+92⇒(2a−6)2−27=p2⇒(2a−6−p)(2a−6+p)=27⇒a=6,p=3⇒b,d=9+−32=6or3Forc=4⇒b+d=3a−4,bd=4a⇒b,d=(3a−4)+−9a2−40a+16=(3a−203)2−(163)22,⇒(3a−203−p)(3a−203+p)=2569⇒a=4,p=0⇒b,d=4,4⇒(a,b,c,d)=(12,6,2,4),(15,10,2,3),(6,6,3,3),(4,4,4,4)uptopermutationsofbandd.
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