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Question Number 195206 by otchereabdullai@gmail.com last updated on 27/Jul/23

Answered by MM42 last updated on 27/Jul/23

$$p\left(a\right)=p\left(b\right)=p\left(c\right)=\frac{3}{4};probabilityofwinningeachrace$$$$\left(i\right)p(a^{\prime }\cap b\cap c^{\prime })=\frac{1}{4}\times \frac{3}{4}\times \frac{1}{4}=\frac{3}{64}$$$$\left(ii\right)p(a\cap b\cap c)=\frac{27}{64}$$$$\left(iii\right)p\left(\mathrm{\Sigma }{abc}^{\prime }\right)=3\times \frac{1}{4}\times \frac{9}{16}=\frac{27}{64}$$

Commented by otchereabdullai@gmail.com last updated on 27/Jul/23

$$thanksalotsir$$

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