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Question Number 195344 by Mingma last updated on 31/Jul/23

Answered by kapoorshah last updated on 31/Jul/23

cos α = cos α ((a^2 + 6^2 − 4^2 )/(2.a.6)) = ((b^2 + 6^2 − 4^2 )/(2.b.6)) ((a^2 + 20)/a) = ((b^2 + 20)/b) a^2 b + 20b = ab^(2 ) + 20a (a − b)(ab − 20) = 0 a = b (rejected) ab = 20

cosα=cosαa2+62−422.a.6=b2+62−422.b.6a2+20a=b2+20ba2b+20b=ab2+20a(a−b)(ab−20)=0a=b(rejected)ab=20

Commented by kapoorshah last updated on 31/Jul/23

Commented by Mingma last updated on 31/Jul/23

Perfect ��

Answered by HeferH last updated on 31/Jul/23

by drawing two heights: 36 − (a + ((b−a)/2))^2 =16 − (((b−a)/2))^2 20 = a^2 + a(b−a) 20 = ab

bydrawingtwoheights:36−(a+b−a2)2=16−(b−a2)220=a2+a(b−a)20=ab

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