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Question Number 195590 by Mingma last updated on 05/Aug/23

Answered by mr W last updated on 05/Aug/23

Commented by mr W last updated on 05/Aug/23

$$\frac{H}{R}=1+\cos \frac{180°}{13}\approx 1.970942$$$$r=radiusofsmalltridecagons$$$$R=radiusofbigtridecagon$$$$H=2h$$$$\frac{r}{R}=\frac{h}{H}=\frac{1}{2}$$$$\frac{areaofsmalltridecagon}{areaofbigtridecagon}={\left(\frac{r}{R}\right)}^2=\frac{1}{4}$$$$\frac{coloredarea}{bigtridecagon}=\frac{2\times areaofsmalltridecagon}{areaofbigtridecagon}=\frac{1}{2}$$$$\Rightarrow answerb)$$

Commented by Mingma last updated on 05/Aug/23

Perfect work, Prof

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