Math Question and Answers


Question and Answers Forum

All Questions Topic List
Geometry Questions
Previous in All Question Next in All Question
Previous in Geometry Next in Geometry
Question Number 195688 by universe last updated on 07/Aug/23

	Answered by mr W last updated on 07/Aug/23

	Commented by York12 last updated on 08/Aug/23

	$p l e a s e b r o t r y t o r e m e m b e r$
	Commented by mr W last updated on 08/Aug/23

	$c^{2} = r^{2} + {(r - \sqrt{{(a + b)}^{2} - r^{2}})}^{2} = r^{2} + {(a + b)}^{2} - 2 r \sqrt{{(a + b)}^{2} - r^{2}}$ $\cos α = \frac{a}{2 r}$ $\cos β = \frac{r^{2} + b^{2} - c^{2}}{2 r b}$ $\cos α = - \cos β$ $\frac{a}{2 r} = - \frac{r^{2} + b^{2} - c^{2}}{2 r b}$ $a = \frac{- r^{2} - b^{2} + r^{2} + {(a + b)}^{2} - 2 r \sqrt{{(a + b)}^{2} - r^{2}}}{b}$ $2 r \sqrt{{(a + b)}^{2} - r^{2}} = a (a + b)$ $4 r^{2} [{(a + b)}^{2} - r^{2}] = a^{2} {(a + b)}^{2}$ $4 r^{2} - 4 {(a + b)}^{2} r^{2} + a^{2} {(a + b)}^{2} = 0$ $r^{2} = \frac{(a + b) [a + b + \sqrt{(2 a + b) b}]}{2}$ $r^{2} = \frac{(a + b) {(\sqrt{2 a + b} + \sqrt{b})}^{2}}{4}$ $\Rightarrow r = \frac{\sqrt{a + b} (\sqrt{2 a + b} + \sqrt{b})}{2} ✓$
	Commented by York12 last updated on 08/Aug/23

	$b r o w h e r e t o l e a r n t h a t$
	Commented by mr W last updated on 08/Aug/23

	$l a w o f c o s i n e s i n t r i g o n o m e t r y i s$ $t e a c h e d i n e v e r y s c h o o l .$
	Commented by York12 last updated on 08/Aug/23

	$n o I d o n o t t a l k a b o u t y o u r s o l u t i o n$ $I a m a s k i n g w h a t b o o k s y o u u s e i n g e n e r a l$
	Commented by mr W last updated on 08/Aug/23

	$i c a n n o t r e m e m b e r a n y m o r e w h a t$ $b o o k s i h a v e u s e d . n o w a d a y s i {d o n}^{'} t$ $u s e a n y b o o k . i f i w a n t t o g e t t o k n o w$ $s o m e t h i n g, i j u s t a s k g o o g l e .$
	Commented by mr W last updated on 08/Aug/23

	$i {c a n}^{'} t r e c o m m e n d y o u a n y b o o k s .$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum