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Question Number 195704 by sonukgindia last updated on 08/Aug/23

Answered by mr W last updated on 08/Aug/23

A=(a+b)^2 A_1 =(((a+b)b)/2) A_2 =((b/( (√((a+b)^2 +b^2 )))))^2 A_1 =((b^2 A_1 )/((a+b)^2 +b^2 )) A_3 =A_1 −2A_2 A_(shade) =A−4A_2 −4A_3 A_(shade) =A−4A_2 −4(A_1 −2A_2 ) A_(shade) =A−4A_1 +4A_2 A_(shade) =A−4A_1 (1−(b^2 /((a+b)^2 +b^2 ))) A_(shade) =A−A_1 ((4(a+b)^2 )/((a+b)^2 +b^2 )) A_(shade) =(a+b)^2 −((2(a+b)^3 b)/((a+b)^2 +b^2 )) A_(shade) =((a^2 (a+b)^2 )/((a+b)^2 +b^2 )) (A_(shaded) /A)=(a^2 /((a+b)^2 +b^2 ))=(a^2 /(a^2 +2b^2 +2ab)) ✓

A=(a+b)2A1=(a+b)b2A2=(b(a+b)2+b2)2A1=b2A1(a+b)2+b2A3=A1−2A2Ashade=A−4A2−4A3Ashade=A−4A2−4(A1−2A2)Ashade=A−4A1+4A2Ashade=A−4A1(1−b2(a+b)2+b2)Ashade=A−A14(a+b)2(a+b)2+b2Ashade=(a+b)2−2(a+b)3b(a+b)2+b2Ashade=a2(a+b)2(a+b)2+b2AshadedA=a2(a+b)2+b2=a2a2+2b2+2ab✓

Commented by mr W last updated on 08/Aug/23

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