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Question Number 195721 by Humble last updated on 08/Aug/23

Answered by mr W last updated on 08/Aug/23

$$volumeofcopper{V}_{cu}=\frac{25}{9.8\times 8.93}=0.286ml$$$$totalvolumeV=\frac{25-20}{9.8\times 1.0}=0.510ml$$$$volumeofbubble{V}_b=0.510-0.286=0.224ml$$$${object}^{\prime }sdensity\rho =\frac{25}{9.8\times 0.510}=5.00g/ml$$

Commented by Humble last updated on 09/Aug/23

$$\mathrm{Great}!!$$

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