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Question Number 195742 by sonukgindia last updated on 09/Aug/23

Answered by MM42 last updated on 09/Aug/23

$$\mathrm{\angle }{\alpha }_i=120\Rightarrow \mathrm{\angle }BAC=\mathrm{\angle }BDF=90$$$$AB=AC\Rightarrow \mathrm{\angle }C=\mathrm{\angle }{B}_{1,2}=45\Rightarrow \mathrm{\angle }{B}_2=\mathrm{\angle }{B}_3=15$$$$\frac{x}{sin15}=\frac{BE}{sin90}\mathrm{\&}\frac{y}{sin15}=\frac{BE}{sin60}$$$$\Rightarrow \frac{x}{y}=\frac{\sqrt{3}}{2}✓$$$$$$

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