All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 195846 by mnjuly1970 last updated on 11/Aug/23
{Ω1=∫0π2x2sin2(x)dx⇒Ω1Ω2=?Ω2=∫0π2xtan(x)dx
Answered by sniper237 last updated on 11/Aug/23
bypartsintegrationΩ2=12Ω1
Terms of Service
Privacy Policy
Contact: info@tinkutara.com