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Question Number 195885 by cortano12 last updated on 12/Aug/23

$$\frac{\mathrm{dy}}{\mathrm{dx}}+\sqrt{\frac{1-{\mathrm{y}}^2}{1-{\mathrm{x}}^2}}=0$$

Answered by mokys last updated on 12/Aug/23

$$\frac{dy}{\sqrt{1-y^2}}+\frac{dx}{\sqrt{1-x^2}}=d\left(0\right)$$$$$$$${sin}^{-1}\left(y\right)+{sin}^{-1}\left(x\right)=c$$

Answered by BaliramKumar last updated on 12/Aug/23

$$x\sqrt{1-y^2}+y\sqrt{1-x^2}=\mathrm{C}$$$$$$

Commented by mokys last updated on 12/Aug/23

$$falsesolution$$

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