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Question Number 195892 by AROUNAMoussa last updated on 12/Aug/23

Answered by mr W last updated on 13/Aug/23

1+(√((4+1)^2 −(4−1)^2 ))+(√((4+2)^2 −(4−2)^2 ))+2 =7+4(√2)

1+(4+1)2−(4−1)2+(4+2)2−(4−2)2+2=7+42

Commented by AROUNAMoussa last updated on 13/Aug/23

Merci mais je n′ai rien compris,veillez donner des detailles !

Mercimaisjen′airiencompris,veillezdonnerdesdetailles!

Commented by mr W last updated on 13/Aug/23

Commented by mr W last updated on 13/Aug/23

length of rectangle =1+a+b+2 a^2 +(4−1)^2 =(4+1)^2 ⇒a=(√((4+1)^2 −(4−1)^2 ))=4 b^2 +(4−2)^2 =(4+2)^2 ⇒b=(√((4+2)^2 −(4−2)^2 ))=4(√2)

lengthofrectangle=1+a+b+2a2+(4−1)2=(4+1)2⇒a=(4+1)2−(4−1)2=4b2+(4−2)2=(4+2)2⇒b=(4+2)2−(4−2)2=42

Commented by AROUNAMoussa last updated on 14/Aug/23

Merci bcp Mr W !

MercibcpMrW!

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