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Question Number 196154 by sonukgindia last updated on 19/Aug/23

Answered by mr W last updated on 19/Aug/23

x^2 =−2(x+2) x^4 =4(x^2 +4x+4)=4(2x)=8x x^6 =8x(−2)(x+2)=−16(x^2 +2x)=−16×(−4)=64 ✓

x2=−2(x+2)x4=4(x2+4x+4)=4(2x)=8xx6=8x(−2)(x+2)=−16(x2+2x)=−16×(−4)=64✓

Answered by BaliramKumar last updated on 19/Aug/23

x^2 +2x+4 =0 (x−2)(x^2 +2x+4) =0(x−2) x ≠ 2 x^3 − 2^3 = 0 x^3 = 8 (x^3 )^2 = 8^2 x^6 = 64

x2+2x+4=0(x−2)(x2+2x+4)=0(x−2)x≠2x3−23=0x3=8(x3)2=82x6=64

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