Math Question and Answers


Question and Answers Forum

All Questions Topic List
Geometry Questions
Previous in All Question Next in All Question
Previous in Geometry Next in Geometry
Question Number 196225 by mr W last updated on 20/Aug/23

Commented by mr W last updated on 20/Aug/23

$f i n d t h e a r e a o f r e d p a r t i n t h e$ $p a r a l l e l o g r a m .$
	Answered by liuxinnan last updated on 20/Aug/23

	$s_{1} + s_{2} + s_{5} + s_{6} = \frac{1}{2} S$ $s_{2} + s_{3} + s_{4} + s_{6} + s_{7} = \frac{1}{2} S$ $s_{7} = 79 + 10 - 8 - 72 = 9$
	Commented by liuxinnan last updated on 20/Aug/23

	Commented by mr W last updated on 20/Aug/23

	$g r e a t!$
	Answered by mr W last updated on 20/Aug/23

	Commented by mr W last updated on 20/Aug/23

	$10 + E + 79 + F = \frac{p a r a l l e l o g r a m}{2}$ $8 + E + 72 + F + r e d = \frac{p a r a l l e l o g r a m}{2}$ $\Rightarrow 8 + E + 72 + F + r e d = 10 + E + 79 + F$ $\Rightarrow r e d = 10 + 79 - 8 - 72 = 9 ✓$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum