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Question Number 1964 by 123456 last updated on 26/Oct/15
d2ydx2=cyx2y(x)=?
Answered by prakash jain last updated on 26/Oct/15
y=kxny″=kn(n−1)xn−2=ckxn−2n(n−1)=cn2−n−c=0n=1±1+4c2y=c1x1+1+4c2+c2x1−1+4c2
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