Question and Answers Forum

All Questions      Topic List

Probability and Statistics Questions

Previous in All Question      Next in All Question      

Previous in Probability and Statistics      Next in Probability and Statistics      

Question Number 196447 by cortano12 last updated on 25/Aug/23

$$\mathrm{n}!=2^{25}\times 3^{13}\times 5^6\times 7^4\times {11}^2\times {13}^2\times 17\times 19\times 23$$$$\mathrm{n}=?$$

Answered by Frix last updated on 25/Aug/23

$$261014182226$$$$4122028$$$$824$$$$16$$$$\Rightarrow$$$$2^{25}\mathrm{is}\mathrm{included}\mathrm{in}28!\mathrm{and}{\mathrm{there}}^{\prime }\mathrm{s}\mathrm{no}29$$$$\Rightarrow$$$$n=28$$

Commented by Rasheed.Sindhi last updated on 25/Aug/23

$$\vee \cap \mathbf{i}\subset \in !$$

Answered by som(math1967) last updated on 25/Aug/23

$$n!=2^{25}\times 3^{13}\times 5^6\times 7^4\times {11}^2\times {13}^2\times 17\times 19\times 23$$$$=28\times 27\times 26\times 25...\times 2\times 1$$$$=2^{25}\times 3^{13}\times 5^6\times 7^4\times {11}^2\times {13}^2\times 17\times 19\times 23$$$$=28!$$$$\therefore n!=28!$$$$n=28$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com