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Question Number 196458 by peter frank last updated on 25/Aug/23
Answered by Peace last updated on 25/Aug/23
∫(sin(y)+ycos(y))dh=∫x(2ln(x)+1)dx⇔+ysin(y)+c=x2ln(x)x2ln(x)−ysin(y)+c=0⇒−π2+c=0⇒x2ln(x)−ysin(y)+π2=f(x,y)solution
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