Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 196525 by Mastermind last updated on 26/Aug/23

Answered by mr W last updated on 27/Aug/23

$$\sqrt{m^2+1}>\sqrt{m^2}=m$$$$\sqrt{m^2+1}<\sqrt{m^2+2m+1}=\sqrt{{(m+1)}^2}=m+1$$$$sincem<\sqrt{m^2+1}<m+1,$$$$\Rightarrow \left[\sqrt{m^2+1}\right]=m$$

Commented by Mastermind last updated on 27/Aug/23

$$\mathrm{Thank}\mathrm{you}\mathrm{so}\mathrm{much}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com