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Question Number 196555 by hardmath last updated on 27/Aug/23

$$\mathrm{In}△\mathrm{ABC}\mathrm{show}\mathrm{that}$$$$\mathrm{\Sigma }\frac{1+\cos \cdot (\mathrm{A}-\mathrm{B})\cdot \cos \mathrm{C}}{{\mathrm{h}}_{\mathbf{C}}\cdot \sec \mathrm{C}}=\frac{3}{2\mathrm{R}}$$

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