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Question Number 19659 by thukada last updated on 14/Aug/17

$$\frac{1+sec\theta }{sec\theta }=\frac{{sin}^2\theta }{1-cos\theta }$$$$$$

Answered by prakash jain last updated on 14/Aug/17

$$\frac{1+\sec \theta }{\sec \theta }=1+\frac{1}{\sec \theta }$$$$=1+\cos \theta =\frac{(1+\cos \theta )(1-\cos \theta )}{(1-\cos \theta )}$$$$=\frac{1-{\cos }^2\theta }{1-\cos \theta }=\frac{{\sin }^2\theta }{1-\cos \theta }◼$$

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