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Question Number 196667 by ERLY last updated on 29/Aug/23

	Answered by Frix last updated on 29/Aug/23

	$No solution .$
	Answered by Phelaire last updated on 29/Aug/23

	$p a s d e s o l u t i o n$
	Answered by Frix last updated on 29/Aug/23

	$We can shift the coordinate system by - z$ $\Rightarrow$ $z = 0 + 0 i$ $Now intersect the lines$ $L_{1} : y = a x + b; (0, - 1) \in L_{1}; a = \tan - \frac{π}{3}$ $L_{2} : y = c x + d; (3, 0) \in L_{2}; c = \tan \frac{2 π}{3}$ $L_{1} : y = - \sqrt{3} x - 1$ $L_{2} : y = - \sqrt{3} x + 3 \sqrt{3}$ $These lines are parallel \Rightarrow no solution$
	Commented by ERLY last updated on 01/Sep/23

	$e x p l i Q u e z$
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