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Question Number 196965 by sonukgindia last updated on 05/Sep/23
Answered by qaz last updated on 05/Sep/23
∫0∞dxx(1+x)(1+x4)=x→x4∫0∞4xdx(1+x4)(1+x)=x→1x∫0∞4x2dx(1+x4)(1+x)=∫0∞2xdx1+x4=π2
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