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Question Number 197010 by sonukgindia last updated on 06/Sep/23

Answered by nikif99 last updated on 06/Sep/23

Triangle inequalitues: 3x−x<10 ⇒2x<10 ⇒x<5 (1) x+3x>10 ⇒4x>10 ⇒x>(5/2) ⇒x≥3 (2) (1)(2) ⇒max x=4 max perim.=x+3x+10=26

Triangleinequalitues:3x−x<10⇒2x<10⇒x<5(1)x+3x>10⇒4x>10⇒x>52⇒x⩾3(2)(1)(2)⇒maxx=4maxperim.=x+3x+10=26

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