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Question Number 197104 by MrGHK last updated on 07/Sep/23

Commented by TheHoneyCat last updated on 08/Sep/23

$$\mathrm{Are}\mathrm{you}\mathrm{looking}\mathrm{for}\mathrm{a}\mathrm{functional}\mathrm{answere}?$$$$\mathrm{because}\mathrm{if}\mathrm{you}\mathrm{are}\mathrm{expecting}\mathrm{a}\mathrm{solution}:$$$$x\left(t\right)=...$$$$\mathrm{then}\mathrm{there}\mathrm{is}\mathrm{an}\mathrm{issue}:y\mathrm{is}\mathrm{not}\mathrm{defined}!$$

Commented by MrGHK last updated on 08/Sep/23

$$yesfunctionalanswer$$

Commented by TheHoneyCat last updated on 08/Sep/23

$${\mathrm{I}}^{\prime }\mathrm{ve}\mathrm{reached}\mathrm{the}\mathrm{point}\mathrm{where}$$$$Y=\frac{3+5i\omega }{2{\omega }^2}X-\frac{i\pi }{{\omega }^2}\theta \left(w\right)$$$$$$$$\mathrm{with}\mathrm{conditions}$$$$\frac{{\mathrm{d}}^{2}y}{\mathrm{d}{t}^2}(t=0)=-1$$$$$$$$\mathrm{I}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{realy}\mathrm{know}\mathrm{how}\mathrm{one}\mathrm{would}\mathrm{go}$$$$\mathrm{further}.$$$$\mathrm{nor},\mathrm{in}\mathrm{fact},\mathrm{if}\mathrm{one}\mathrm{can}...$$

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