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Question Number 197248 by hardmath last updated on 11/Sep/23

a,b,c∈R  ((a + 2b − 3ac)/(3ac))  =  ((a + 4b − bc)/b)  Find:   ((2b)/a) − ((3a)/b)

a,b,cRa+2b3ac3ac=a+4bbcbFind:2ba3ab

Commented by Frix last updated on 11/Sep/23

−(((c+1)(3c^2 −15c+1))/(2c))±(((c−1)(√(9c^4 −90c^3 +231c^2 −6c+1)))/(2c))

(c+1)(3c215c+1)2c±(c1)9c490c3+231c26c+12c

Commented by hardmath last updated on 11/Sep/23

Ser, ansver: 11

Ser,ansver:11

Commented by Frix last updated on 12/Sep/23

You must be kidding. The given equation  has 3 variables. We can solve for one of these.  It′s not possible to get a unique solution.

Youmustbekidding.Thegivenequationhas3variables.Wecansolveforoneofthese.Itsnotpossibletogetauniquesolution.

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