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Question Number 197281 by cortano12 last updated on 12/Sep/23

$$\underset{x\to 0}{\lim }\frac{\sin \mathrm{x}-\mathrm{x}+{2\mathrm{x}}^5}{{3\mathrm{x}}^3}=?$$

Answered by MM42 last updated on 12/Sep/23

$${lim}_{x\to 0}\frac{-\frac{1}{6}{x}^3+2x^5}{3x^3}=-\frac{1}{18}✓$$

Answered by tri26112004 last updated on 13/Sep/23

$$=\underset{x\to 0}{\lim }\frac{cosx+10x^4-1}{9x^2}$$$$=\underset{x\to 0}{\lim }\frac{-sinx+40x^3}{18x}$$$$=\underset{x\to 0}{\lim }\frac{-cosx+120x^2}{18}$$$$=-\frac{1}{18}$$

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