answer to the question number 197017 AF=FI & AG=GT⇒FG=(1/2)IJ=(1/6)BC △FGH is squilatral ⇒ △FGH≈△ABC ⇒(S_(FGH) /S


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Question Number 197287 by MM42 last updated on 12/Sep/23

$a n s w e r t o t h e q u e s t i o n n u m b e r$ $197017$ $A F = F I & A G = G T \Rightarrow F G = \frac{1}{2} I J = \frac{1}{6} B C$ $△ F G H i s s q u i l a t r a l \Rightarrow △ F G H \approx △ A B C$ $\Rightarrow \frac{S_{F G H}}{S_{S B C}} = \frac{1}{36} ✓$
Commented by MM42 last updated on 12/Sep/23

Commented by MM42 last updated on 12/Sep/23

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