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Question Number 197299 by bbbbbbbb last updated on 12/Sep/23

((−64))^(1/6) −((−10))^(1/(10)) =?  I need so much plz

6461010=?Ineedsomuchplz

Answered by Frix last updated on 13/Sep/23

∀n∈N\{0}: −n=ne^(iπ)  ⇒  ((−n))^(1/k) =(n)^(1/k) e^(i(π/k)) =(n)^(1/k) (cos (π/k) +i sin (π/k))

nN{0}:n=neiπnk=nkeiπk=nk(cosπk+isinπk)

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