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Question Number 197310 by sonukgindia last updated on 13/Sep/23

Answered by Frix last updated on 13/Sep/23

$$\left(1\right)z^2-7z+11=1$$$$\Rightarrow z=2\vee z=5$$$$\left(2\right)\ln (z^2-3z+{\mathrm{e}}^2)=0$$$$\Rightarrow z=\frac{3}{2}\mp \frac{\sqrt{{4\mathrm{e}}^2-13}}{2}\mathrm{i}$$$$\left(3\right)z^2-7z+11=-1\wedge \ln (z^2-3z+{\mathrm{e}}^2)=2n$$$$\Rightarrow z=3$$

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