Math Question and Answers


Question and Answers Forum

All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 197524 by sonukgindia last updated on 20/Sep/23

	Answered by som(math1967) last updated on 20/Sep/23
	$2arctan((x/(1+(√(1+x^2 ))))) =arctan{(((2x)/(1+(√(1+x^2 ))))/(1−(x^2 /((1+(√(1+x^2 )))^2 ))))} =arctan{((2x)/(1+(√(1+x^2 ))))×(((1+(√(1+x^2 )))^2 )/(2+2(√(1+x^2 ))))} =arctan(((2x)/2))=arctanx$
	$2 arc t a n (\frac{x}{1 + \sqrt{1 + x^{2}}})$ $= arc t a n {\frac{\frac{2 x}{1 + \sqrt{1 + x^{2}}}}{1 - \frac{x^{2}}{{(1 + \sqrt{1 + x^{2}})}^{2}}}}$ $= arc t a n {\frac{2 x}{1 + \sqrt{1 + x^{2}}} \times \frac{{(1 + \sqrt{1 + x^{2}})}^{2}}{2 + 2 \sqrt{1 + x^{2}}}}$ $= arc t a n (\frac{2 x}{2}) = arc t a n x$
	Answered by Mathspace last updated on 20/Sep/23

	$x = t a n t \Rightarrow$ $2 a r c t a n (\frac{x}{1 + \sqrt{1 + x^{2}}})$ $= 2 a r t a n (\frac{t a n t}{1 + \sqrt{1 + {t a n}^{2} t}})$ $= 2 a r c t a n (\frac{t a n t}{1 + \frac{1}{c o s t}})$ $= 2 a r c t a n (\frac{c o s t t a n t}{1 + c o s t})$ $= 2 a r c t a n (\frac{s i n t}{1 + c o s t})$ $= 2 a r c t a n (\frac{2 s i n (\frac{t}{2}) c o s (\frac{t}{2})}{2 {c o s}^{2} (\frac{t}{2})})$ $= 2 a r c t a n (t a n (\frac{t}{2}))$ $= 2 . \frac{t}{2} = t = a r c t a n x$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum