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Question Number 197548 by cortano12 last updated on 21/Sep/23

$$\underset{x\to -\mathrm{\infty }}{\lim }{\left(\frac{4\mathrm{x}-\sqrt{{4\mathrm{x}}^2+5}}{2\mathrm{x}-1}\right)}^{\mathrm{bx}}=?$$

Answered by MM42 last updated on 21/Sep/23

$${lim}_{x\to -\mathrm{\infty }}{\left(\frac{4x-\mid 2x\mid }{2x-1}\right)}^{bx}={lim}_{x\to -\mathrm{\infty }}{\left(3\right)}^{bx}=\{\begin{array}{l}0;b>0\\ +\mathrm{\infty };b<0\end{array}$$

Commented by cortano12 last updated on 21/Sep/23

$$\mathrm{wrong}$$

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