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Question Number 197636 by universe last updated on 25/Sep/23

Answered by mr W last updated on 25/Sep/23

s=x+y (x+3)^2 +y^2 =(8(√2))^2 (x+3)^2 +(s−x)^2 =128 2(x+3)+2(s−x)(−1)=0 ⇒s=2x+3 (x+3)^2 +(2x+3−x)^2 =128 ⇒x+3=8 ⇒x=5 ⇒s_(max) =2×5+3=13 ✓

s=x+y(x+3)2+y2=(82)2(x+3)2+(s−x)2=1282(x+3)+2(s−x)(−1)=0⇒s=2x+3(x+3)2+(2x+3−x)2=128⇒x+3=8⇒x=5⇒smax=2×5+3=13✓

Commented by universe last updated on 25/Sep/23

thanks sir

thankssir

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