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Question Number 197644 by gungun last updated on 25/Sep/23

Commented by gungun last updated on 25/Sep/23

$f i n d t h e p i n k a r e a$
	Answered by Rasheed.Sindhi last updated on 25/Sep/23

	$P i n k a r e a i n t e r m s o f R & r :$ $A_{p} = π (R^{2} - r^{2})$ $O n t h e o t h e r h a n d$ $x^{2} + r^{2} = R^{2}$ $o r R^{2} - r^{2} = x^{2}$ $T h e r e f o r e$ $A_{p} = π x^{2}$
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