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Question Number 197717 by a.lgnaoui last updated on 27/Sep/23

$$\measuredangle \mathbf{A}=62\measuredangle \mathbf{C}=43$$$$\mathbf{Determiner}:\mathrm{a}=\measuredangle \mathbf{B}\mathrm{c}=\measuredangle \mathbf{D}\mathrm{b}=\measuredangle \mathbf{F}$$

Commented by a.lgnaoui last updated on 27/Sep/23

$$\measuredangle EDF=62?$$

Commented by a.lgnaoui last updated on 27/Sep/23

Commented by som(math1967) last updated on 27/Sep/23

$$\measuredangle AEC=180-(62+43)=75$$$$\therefore \mathrm{\angle }ABD=180-75=105$$$$\mathrm{\angle }EDF=62$$$$\mathrm{\angle }EFD=180-(62+105)=13$$

Commented by som(math1967) last updated on 27/Sep/23

$$yes,\mathrm{\angle }BDE+\mathrm{\angle }BAE=180$$$$\mathrm{\angle }BDE+\mathrm{\angle }EDF=180$$$$\therefore \mathrm{\angle }BDE+\mathrm{\angle }BAE=\mathrm{\angle }BDE+\mathrm{\angle }EDF$$$$\therefore \mathrm{\angle }BAE=\mathrm{\angle }EDF=62$$

Commented by a.lgnaoui last updated on 27/Sep/23

$$\mathrm{thanks}$$

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