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Question Number 197767 by AR19 last updated on 28/Sep/23

Commented by Frix last updated on 28/Sep/23

∫(√(x^3 +1))dx=x _2 F_1  (−(1/2), (1/3); (4/3); −x^3 ) +C

x3+1dx=x2F1(12,13;43;x3)+C

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