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Question Number 197895 by tri26112004 last updated on 02/Oct/23

$$Solvetheequation:$$$$x^4-x^3-4x^2+3x+2=0$$

Answered by Frix last updated on 02/Oct/23

$$(x-2)(x^3+x^2-2x-1)=0$$$$x_1=2$$$$\mathrm{Use}\mathrm{trigonometric}\mathrm{method}$$$$x_2=-\frac{1+2\sqrt{7}\cos \frac{\pi +{2\sin }^{-1}\frac{\sqrt{7}}{14}}{6}}{3}$$$$x_3=-\frac{1+2\sqrt{7}\sin \frac{{\sin }^{-1}\frac{\sqrt{7}}{14}}{3}}{3}$$$$x_4=\frac{-1+2\sqrt{7}\sin \frac{\pi +{\sin }^{-1}\frac{\sqrt{7}}{14}}{3}}{3}$$

Commented by Frix last updated on 03/Oct/23

$$\mathrm{Read}\mathrm{the}\mathrm{comments}\mathrm{to}\mathrm{question}114263$$

Commented by tri26112004 last updated on 03/Oct/23

$$Canyouexplainitmorespecifically¿$$

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