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Question Number 197944 by liuxinnan last updated on 05/Oct/23

tan(π/(12))=((sinα−sin(π/(12)))/(cosα+cos(π/(12))))  α=?

tanπ12=sinαsinπ12cosα+cosπ12α=?

Answered by MM42 last updated on 05/Oct/23

sin(π/(12))×cosα+sin(π/(12))×cos(π/(12))=sinα×cos(π/(12))−sin(π/(12))×cos(π/(12))  ⇒sin(α−(π/(12)))=2sin(π/(12))×cos(π/(12))=sin(π/6)  ⇒ { ((α=2kπ+(π/4)  ✓)),((α=2kπ+((11π)/(12))   ×)) :}

sinπ12×cosα+sinπ12×cosπ12=sinα×cosπ12sinπ12×cosπ12sin(απ12)=2sinπ12×cosπ12=sinπ6{α=2kπ+π4α=2kπ+11π12×

Commented by MM42 last updated on 05/Oct/23

Sir  “W”  in the denominator of the fraction  is written “ cosα+cos(π/(12)) ”

SirWinthedenominatorofthefractioniswrittencosα+cosπ12

Commented by mr W last updated on 06/Oct/23

yes. i noticed it also, but too late.

yes.inoticeditalso,buttoolate.

Commented by MM42 last updated on 06/Oct/23

 ⋛M

M

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