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Question Number 197947 by mnjuly1970 last updated on 05/Oct/23
calculate…L=limn→∞(1+12)(1+13)…(1+1n)n=?
Answered by MM42 last updated on 05/Oct/23
A=limn→∞(32×43×...×nn−1×n+1n)1nlnA=limn→∞ln(n+12)1n=limn→∞ln(n+12)n=0⇒A=1✓
Commented by mnjuly1970 last updated on 05/Oct/23
thxalotsir...
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