Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 198147 by mr W last updated on 11/Oct/23

if a,x,y,b is an AP and a,p,q,b is a GP.  prove that xy≥pq.  (with a, b >0)

ifa,x,y,bisanAPanda,p,q,bisaGP.provethatxypq.(witha,b>0)

Answered by deleteduser1 last updated on 11/Oct/23

p^2 =aq;q^2 =pb⇒p^2 q^2 =abpq⇒pq=ab  2x=a+y;2y=x+b⇒4xy=(a+y)(x+b)  3xy=ax+ab+yb≥^? 3pq=3ab  ⇔ax+yb≥2ab  ⇔a(a+d)+(a+2d)(a+3d)≥2(a)(a+3d)  a^2 +ad+a^2 +3ad+2ad+6d^2 ≥2a^2 +6ad  ⇔d^2 ≥0(true).. Hence 3xy≥3ab⇒xy≥ab=pq  Equality holds when d=0 ⇒ a=b=x=y=p=q

p2=aq;q2=pbp2q2=abpqpq=ab2x=a+y;2y=x+b4xy=(a+y)(x+b)3xy=ax+ab+yb?3pq=3abax+yb2aba(a+d)+(a+2d)(a+3d)2(a)(a+3d)a2+ad+a2+3ad+2ad+6d22a2+6add20(true)..Hence3xy3abxyab=pqEqualityholdswhend=0a=b=x=y=p=q

Commented by mr W last updated on 11/Oct/23

��

Terms of Service

Privacy Policy

Contact: info@tinkutara.com