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Question Number 198786 by sonukgindia last updated on 24/Oct/23

Commented by Frix last updated on 24/Oct/23

$If a, b, c, d, e \in N :$ $1 . a b c = 2^{3} \times 3$ $2 . b c d = 2^{2} \times 3 \times 5$ $3 . c d e = 2^{3} \times 3 \times 5$ $4 . d e a = 2^{2} \times 3 \times 5$ $\Rightarrow d = 5$ $1 . a b c = 2^{3} \times 3$ $2 . b c = 2^{2} \times 3$ $\Rightarrow a = 2$ $4 . \Rightarrow e = 6$ $3 . \Rightarrow c = 4$ $1 . \Rightarrow b = 3$
Commented by mr W last updated on 24/Oct/23

$s o n u k g i n d i a s i r :$ $w h y {d o n}^{'} t y o u g i v e a n y f e e d b a c k a n d$ $n e v e r r e p l y w h a t o t h e r p e o p l e a s k$ $y o u ?$
Commented by sonukgindia last updated on 24/Oct/23

$s o r r y i w i l l g i v e$
Commented by mr W last updated on 24/Oct/23

$t h a n k s f o r t h i s r e p l y!$
	Answered by Frix last updated on 24/Oct/23

	$One of \infty solutions :$ $a = 2 b = 3 c = 4 d = 5 e = 6$
	Answered by mr W last updated on 24/Oct/23

	$5 u n k n o w n s : A, B, C, D, E$ $b u t o n l y 4 e q u a t i o n s$ $\Rightarrow i n f i n i t e l y m a n y s o l u t i o n s!$
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