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Question Number 198860 by cherokeesay last updated on 25/Oct/23

	Answered by mr W last updated on 25/Oct/23

	$D) i s c o r r e c t .$ $t h e f o r c e m o v e d t h e b l o c k t o a h e i g h t$ $a \sin θ, t h e w o r k d o n e i s w a \sin θ .$ $t h e f o r c e p u l l e d t h e s p r i n g t o a l e n g t h$ $a θ, t h e w o r k d o n e i s \frac{k {(a θ)}^{2}}{2} .$ $s o t h e t o t a l w o r k d o n e b y t h e f o r c e i s$ $w a \sin θ + \frac{{k a}^{2} θ^{2}}{2} .$
	Commented by cherokeesay last updated on 25/Oct/23

	$N i c e! t h a n k y o u m a s t e r!$
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