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Question Number 199006 by adhigenz last updated on 26/Oct/23

$$\mathrm{Given}\mathrm{that}ABCD\mathrm{is}\mathrm{a}\mathrm{trapezium}\mathrm{such}\mathrm{that}AD//BC.$$$$\mathrm{The}\mathrm{centroid}\mathrm{of}△ABD\mathrm{lies}\mathrm{on}\mathrm{the}\mathrm{bisector}\mathrm{of}\mathrm{\angle }BCD.$$$$\mathrm{Show}\mathrm{that}\mathrm{the}\mathrm{centroid}\mathrm{of}△ABC\mathrm{lies}\mathrm{on}\mathrm{the}\mathrm{bisector}\mathrm{of}\mathrm{\angle }ADC.$$

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