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Question Number 199073 by pascal889 last updated on 27/Oct/23

$$\mid 3-3\mathrm{x}\mid >9$$$$$$$$\mathrm{solve}\mathrm{fir}\mathrm{x}$$$$$$$$\mathrm{ss}$$$$$$

Answered by Rasheed.Sindhi last updated on 27/Oct/23

$$\mid 3-3\mathrm{x}\mid >9$$$$+(3-3x)>9\mid -(3-3x)>9$$$$\cancel{3}-3x-\cancel{3}>9-3\mid -\cancel{3}+3x+\cancel{3}>9+3$$$$\frac{-3x}{-3}<\frac{6}{-3}\mid \frac{3x}{3}>\frac{12}{3}$$$$x<-2\mid x>4$$

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