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Question Number 199176 by cortano12 last updated on 29/Oct/23
Iff(x)=(x2−4x)sin4xfindf(6)(x).
Answered by MM42 last updated on 29/Oct/23
f=u.v⇒f(n)=∑ni=0(ni)×u(n−i)×v(i)let:u=x2−4x&v=sin4x⇒f(6)(x)=30×44sin4x+6×45×(2x−4)cos4x−46×(x2−4x)sin4x✓
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