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Question Number 199259 by hardmath last updated on 30/Oct/23

Commented by Frix last updated on 30/Oct/23

$$\sqrt{\sqrt{12345689654321233\pm 5333334096\sqrt{12345679}}}=$$$$=\sqrt{111111127\pm 24\sqrt{12345679}}=$$$$=\pm 4+3\sqrt{12345679}$$$$\sqrt[3]{x-y}=\sqrt[4]{8}=2$$

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