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Question Number 199339 by necx122 last updated on 01/Nov/23

Commented by necx122 last updated on 01/Nov/23

$$find\mathrm{\angle }QSRwhereOisthecentre$$$$\mathrm{\angle }OTQ=15,\mathrm{\angle }TOR=110$$

Commented by deleteduser1 last updated on 01/Nov/23

$$20°$$

Answered by MM42 last updated on 01/Nov/23

$$20$$

Commented by necx122 last updated on 01/Nov/23

oh! I've seen my mistake, thank you, sirs. angle at the centre is twice the angle at the circumference

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